Stoichiometry! Answer to Part 2

Hello once again my fellow stoichiometrists (I don't even know if that's a real word.  I doubt it, but that's just what I'm going to use.)  Yesterday, I left you with a problem to try to solve on your own:

How many grams of H2SO4 are needed to make 350 mL of a 0.179 M solution?

Did you have any luck solving it?  If not, don't fear.  Stoichiometry is something that takes practice (like any other thing) but not just any kind of practice, but perfect practice (the more you get right while solving the right way, the better you'll get).  It doesn't help to practice something the wrong way.

Here's the solution:

0.350 L H2SO4 * 0.179 mol H2SO4 * 98.077 g H2SO4 = 6.144 g H2SO4

 1 L H2SO4            1 mol H2SO4

If you got 6.145 g, that's ok.  It all just depends on how you rounded (depending on the periodic table you used and if you used three places after the decimal, the actual answer was 6.1445 g).  In a later post, I will explain how, even though the last number was 5, I got 6.144 g instead of 6.145 g.  So stay tuned for that post!  In the mean time, I'll give you guys a rest to let your brain stop smoldering.

To find out more about stoichiometry, I suggest going to one of these websites:

chemistry.about.com

chem4kids.com

chemed.chem.purdue.edu

chemteam.info

Have a great day!